Table A. Number of oxgen bubbles
Test Tube | Distilled water | Tap water |
1 | 21 | 19 |
2 | 20 | 18 |
3 | 18 | 17 |
4 | 17 | 19 |
5 | 18 | 20 |
6 | 18 | 20 |
7 | 19 | 20 |
8 | 15 | 21 |
9 | 22 | 29 |
10 | 17 | 21 |
Here are the steps done to statistically treat the data above:
a. Hypotheses:
Null Hypothesis: Xdistilled water = Xtap water
Alternative: Xdistilled water ≠ Xtap water
b. Significance level: .05
c. Results
Group Statistics
number of oxygen bubbles | type of water | N | Mean | Std. Deviation | Std. Error Mean |
distilled water | 10 | 18.5000 | 2.06828 | .65405 | |
tap water | 10 | 20.4000 | 3.27278 | 1.03494 |
Independent Samples Test
number of oxygen bubbles | t-test for Equality of Means | ||||||
t | df | Sig. (2-tailed) | Mean Difference | Std. Error Difference | 95% Confidence Interval of the Difference | ||
-1.552 | 18 | .138 | -1.9000 | 1.22429 | Lower | Upper | |
-4.47214 | .67214 |
The t -vale of -1.552, with degree of freedom of 18 has a significance level of .138, which is greater than the significance level of .05.
Therefore the null hypothesis is rejected.
simple, comprehensive. keep up.
ReplyDelete